Math, asked by pranjaljain25, 10 months ago

calculate the compound intrest for second year on 8000 invested for 3 year at 10% p. a. ​

Answers

Answered by ayyappanayyanan
6

Answer:

₹ 880

Step-by-step explanation:

8000×1×10/100

Amount end in 1st year = 8800

R=10%

8800×1×10/100

880 is the answer

Answered by Anonymous
112

\LARGE{\underline{\underline{\sf{Given}}}}\\

  • Principal amount = Rs 8000
  • Amount invested for 3 years
  • Rate at which amount was invested is 10 %
  • Invested at compound interest [compounded annually ]

\LARGE{\underline{\underline{\sf{To \; Find}}}}\\

  • Compound interest for 2nd year .

\LARGE{\underline{\underline{\sf{Solution}}}}\\

\large{\boxed{\sf{Formula \;=\; principal \; amount\; (1 + \frac{Rate}{100}) ^{(Time \;period)} }}}\\

\large{\underline{\underline{\sf{\purple{Interest \; on \; 3\; years}}}}}\\

Using the above mentioned formula :-

\sf{\implies Compound \; interest = 8000[1 + \frac{10}{100}] ^{3} }\\

We have to find interest only so

\sf{\implies \; Interest \; =\; 8000[\frac{11}{10}] ^{3} - 8000}\\

\sf{\implies\; Interest\; = [ 8 \times 11 \times 11 \times 11 ] - 8000}\\

\sf{\implies \; Interest \; =\;[ 8 \times 1331 ] - 8000}\\

\sf{\implies \; Interest \; = 10648 - 8000}\\

{\underline{\underline{\sf{\purple{\implies \;INTEREST \; = \; 2648}}}}}

\large{\underline{\underline{\sf{\purple{Interest \; on \; 2 \; years}}}}}\\

\sf{\implies \; interest = \; [8000\times (1+  \frac{10}{100} )^{2}] - 8000  }\\

\sf{\implies \; Interest \; = 8000(\frac{110}{100} )^{2} - 8000}\\

\sf{\implies \; Interest \; = 80[121] - 8000}\\

\sf{\implies \; Interest\; = \; 9680 - 8000 = 1680}\\

{\underline{\underline{\sf{\purple{\implies \;INTEREST\; = 1680}}}}}\\

\large{\underline{\underline{\sf{\purple{Interest \; on \; 1\; year}}}}}\\

\sf{\implies \; Interest \; = 8000[1+ \frac{10}{100} ]^{1} - 8000 }\\

\sf{\implies \; Interest \; = 8000[ \frac{110}{100} ] -8000}\\

\sf{\implies \; Interest \; = \; 8800-8000}\\

{\underline{\underline{\sf{\purple{\implies \; INTEREST \; = \; 800}}}}}\\

Interest for 2nd year = Interest for 2 years - Interest for 1 year

= 1680 - 800 = 880 rupees

{\underline{\underline{\sf{\pink{\implies Answer \; is \; Rs \; 880 }}}}}\\

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