Question

calculate the concentration of a solution which is prepared by dissolving 15g of kcl in 185 g of water ..... please give rhe right. don't spam...​

Answer 1

Answer:

7.5

Explanation:

concentration of a solution =amount of solute x100/amount of solution=15x100/185+15=3x100/40=7.5

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Answer 2

Answer:

The concentration of a solution is approximately 7.5%

Explanation:

As per the given data,

• Mass of solute (KCl salt) = 15 g.

• Mass of solvent (water) = 185 g.

• We know that mass of solution can be calculated by adding the mass of solute and the mass of solvent.

Thus, the mass of solution = mass of solute + mass of solvent

= 15g + 185g

= 200 g

∴ Mass of solution = 200 g.

To calculate:

• The concentration of the solution= $(\frac{mass of solute}{mass of solution})$ x 100

⇒ $\frac{15}{200}$ x 100

⇒ (0.075) × 100 = 7.5% (approx.)

Therefore, the concentration of a solution which is prepared by dissolving 15g of $KCl$ in 185 g of water is found to be approximately 7.5%

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