Chemistry, asked by eswarcirc7981, 1 year ago

Calculate the concentration of all ions present in 57.9 mg nh4br in 500 ml solution

Answers

Answered by Raunakask
0

Sorry I don't know......

Answered by CarlynBronk
0

The concentration of ammonium and bromide ions in the solution is 1.18\times 10^{-3}M for both

Explanation:

To calculate the volume of solution, we use the equation used to calculate the molarity of solution:

\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}

Given mass of ammonium bromide = 57.9 mg = 0.0579 g   (Conversion factor:  1 g = 1000 mg)

Molar mass of ammonium bromide = 98 g/mol

Volume of solution = 500 mL

Putting values in above equation, we get:

\text{Molarity of solution}=\frac{0.0579\times 1000}{98g/mol\times 500}\\\\\text{Molarity of solution}=1.18\times 10^{-3}M

1 mole of ammonium bromide produces 1 mole of ammonium ions and 1 mole of bromide ions

So, concentration of ammonium ions = (1\times 1.18\times 10^{-3})=1.18\times 10^{-3}M

Concentration of bromide ions = (1\times 1.18\times 10^{-3})=1.18\times 10^{-3}M

Learn more about molarity:

https://brainly.in/question/9439794

https://brainly.in/question/10859900

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