Question

calculate the concentration of aqua solution of glucose obtained by dissolving 10 gram of glucose in 1000 gram of water.​

Answer 1

Answer:

0,05 M

Explanation:

calculate the concentration of aqua solution of glucose obtained by dissolving 10 gram of glucose in 1000 gram of water.

= (10 x 1.000) / (180 x 1000)

= 10.000/180.000

= 0,05 M

Answer 2

$\Large{ \cdot{ \rm{ \underline{ \red{Concetration \: of \: given \: solution:}}}}}$

✦GiveN:

• Mass of glucose = 10 g
• Mass of water = 1000g

✦To FinD:

• Mass by mass concentration of glucose solution.

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$\Large{ \cdot{ \rm{ \underline{ \red{Concept \: used:}}}}}$

♦️ Mass by Mass percentage:

The mass of solute in grams dissolved in 100 g of the solution. As here the solution of 1000 g(Solvent), we have to change in such a way that we can find concentration according to 100g solution. Generally this method is used, when the concentration of solution is asked, but not mentioned that whether it is Volume by Volume percentage etc. So it is calculated as,

${ \star \: {\boxed{ \purple{ \rm{Mass \: by \: Mass \: \% = \frac{mass \: of \: solute(g)}{mass \: of \: solution(g)} \times 100}}}}}$

⚠️ Always remember that, mass of solute is divided by mass of solution not solvent. Mass of solution is mass of solute + mass of solvent.

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$\Large{ \cdot{ \rm{ \underline{ \red{Answer:}}}}}$

By using formula,

$\large{ \rm{ \cdot{Mass \: of \: solute = 10 g}}} \\ \\ \large{ \rm{ \cdot{Mass \: of \: solution = 10 g + 1000 g = 1010g}}} \\ \\ \large{ \rm{ \rightarrow \: Mass \: by \: Mass\% = \frac{10}{1010} \times 100}} \\ \\ \large{ \rm{ \rightarrow \: Mass \: by \: Mass\% = \cancel{ \frac{1000}{1010}\%}}} \\ \\ \large{ \rm{ \rightarrow \: Mass \: by \: Mass\% \approx \: \boxed{ \rm{ \green{0.991\%}}}}} \\ \\ \large{ \therefore{ \underline{ \rm{ \purple{ \underline{Hence, \: solved \: \dag}}}}}}$

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