Question

calculate the concentration of aqueous solution of glucose obtained by dissolving 10 gm of glucose in 1000 gm of water
​

Answer 1

Answer:

10/11

Step-by-step explanation:

We know that the mass of solute us 10 gm

and mass of solvent is 1000 gm

'

so mass of solution is 1100 gm '

apply the formula of mass upon mass

which is mass of solvent * 100

mass of solution

now calculate

10/1100 * 100

which is 10/11

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Answer 2

Given:

10 gm of glucose is dissolved in 1000 gm of water.

To find:

The concentration of the aqueous solution of glucose.

Solution:

From given, we have,

The weight of glucose = 10 gm

The molecular weight of glucose = 180 gm/mol

Number of moles of glucose = 10/180 = 1/18

The mass of water = 1000 g

The molality of glucose = no of moles of glucose/mass of solvent in kg

= (1/18)/1 molal

= 0.055 molal

The mass of solution = 1000 + 10 = 1010 g

The concentration of glucose = w/W % = mass of solute/mass of solution × 100

= 10/1010 × 100 = 1000/1010 = 0.99 %

∴ The concentration of glucose is 0.99 % w/W .