Calculate the concentration of hydrogen ion in 0.62M NaOH solution
Answers
Answer:
K
w = [H
3
O
+][OH-] = 1.0 x 10-14
[H
3
O
+] x 0.62 M = 1.0 x 10-14
[H
+] = (1.0 x 10-14/ 0.62) = 1.6 x 10-14
M
Explanation:
hope it helps you
Answer:
The concentration of hydrogen ions in a 0.62M NaOH solution is 1.61 × M.
Explanation:
Given that,
The molarity of the NaOH solution is 0.62M
So,
0.62 M NaOH ==> 0.62 M Na⁺ + 0.62 M OH⁻
In a 0.62 M NaOH solution, the concentration of OH ions is equal to the NaOH concentration, which is 0.62 M.
[OH⁻] = 0.62M
From the equation for the self-ionization of water, we get
H₂O ⇌ H⁺ + OH⁻
The hydrogen ions (H⁺) concentration in the NaOH solution can be calculated using the hydroxide ions (OH⁻) concentration in the NaOH solution and the equilibrium constant (Kw).
Kw = 1.0 ×
Kw = [H⁺][OH⁻]
[H⁺] = Kw / [OH⁻]
= 1.0 × / 0.62
= 1.61 × M
The concentration of H⁺ ions = 1.61 × M.
Therefore, the concentration of H⁺ ions in a 0.62M NaOH solution is 1.61 × M.
To know more about the concentration of hydrogen ions, visit the link below:
https://brainly.in/question/2946067
To know more about the molarity, visit the link below:
https://brainly.in/question/1159016
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