Calculate the concentration of nitric acid in mole per litre in a sample of 69g HNO3 in 10ml of a solution in water
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molar mass of HNO3 = 63g
given mass =69g
no. of moles = 69÷63= 1.09 mols
volume = 10 ml
molarity = no of moles÷ volume
M = (1.09×1000) ÷ 10
10900 ÷ 10 = 1090 mols / litre
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