Question

Calculate the concentration of nitric acid in moles

Answer 1

Given:-

Mass percent of nitric acid in the sample = 69 %

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Thus, 100 g of nitric acid contains 69 g of nitric acid by mass.

Molar mass of nitric acid (HNO3)

=> 1 + 14 + 16(3)

=> 1 + 14 + 48

=> 63g/mol

Now,

For calculating the number of moles in a given 69g of nitric acid.....

No. of moles = mass/molar mass

No. of moles = 69g/63gmol-1

=> 1.096mol

Now,

Volume of 100g of nitric acid solution...

=> Mass of Sol./ Density of Sol.

=> 100g/1.41gmL-1

=> 70.92mL

=> 70.92 × 10^-3L

Concentration of nitric acid

=> No. of moles/ Volume of 100g of HNO3 Sol.

=> 1.095mol/70.92 × 10^-3L

=> 15.44 mol/Litre

The concentration of given HNO3 is 15.44mol/litre...

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Hope it helps you⭐

Answer 2

Given:-

⭐Mass percent of nitric acid in the sample = 69

⭐Thus, 100 g of nitric acid contains 69 g of nitric acid by mass.

⭐Molar mass of nitric acid (HNO3)

1 + 14 + 16(3)

1 + 14 + 48

63g/mol

⭐For calculating no. of moles in a given 69g of nitric acid:-

No. of moles = mass/molar mass

No. of moles = 69g/63gmol-1

1.096mol

⭐Volume of 100g of nitric acid solution:-

=> Mass of Sol./ Density of Sol.:-

100g/1.41gmL-1

70.92mL

70.92 × 10^-3L

⭐Concentration of nitric acid:-

No. of moles/ Volume of 100g of HNO3 Sol.

1.095mol/70.92 × 10^-3L

15.44 mol/Litre

✔✔✔TheconcentrationofgivenHNO3is15.44mol/litre♥️♥️