calculate the concentration of nitric acid in moles of nitric acid in moles of liters in a sample which has density , 1.42gram per litter and the mass percentage in nitric acid is 69%
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The density of the solution is 1.41 g/mL.
1000 g of the solution will have a volume =
Density
Mass
=
1.41
1000
=709 ml.
The mass per cent of nitric acid is 69%.
1000 g of the solution will have 1000×
100
69
=690 g of nitric acid.
The molarity of solution is
Molar mass of nitric acid ×Volume of solution
Mass of nitric acid
=
63×709
690
=0.0155 M.
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