Question

Calculate the concentration of nitric acid in moles per liter in a sample which has a density, 1.41 g M/L and mass percent of nitric acid in it being 69%. ​

Answer 1

Answer:

15.44 M

Explanation: Given density of aqueous solution is 1.41 gm/ml of which 69% is nitric acid (HNO3).

So, 69% of 1.41 => 1.41 x 69/100 = 0.9729

Density of Nitric Acid = 0.9729 gm/ml

Now, Density = Mass/Volume. So,

0.9729 = Mass of HNO3/1000ml

Mass of HNO3 = 972.9 gm

No. of moles of HNO3 = Mass of HNO3/Molar mass of HNO3

                                       = 972.9/63                

                                       = 15.44 mol.

So Molarity of HNO3 = No. of moles of HNO3/Volume of Solution

                                    = 15.44/1 L

                                    = 15.44 M

(Note) : We find molarity because in the question it is asked to moles per litre which is molarity(M).

Answer 2

★ Answer :

→ Refer to the attachment.