Question

Calculate the concentration of nitric acid in moles per litre in a sample which has a density, 1.41 g mL - 1 and the mass percent of nitric acid in it being 69%.

Answer 1

Answer:

      Molarity = 15.44M

Explanation:

moles per litre - Molarity (M)  ,  Nitric Acid - Molecular Mass = 1+(3×16)+14 = 63u

M = 10 × density × mass% / Molecular Mass

M = 10 × 1.41 × 69 / 63

M = 14.1 × 23 / 21

Molarity = 15.44M

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Answer 2

Explanation:

The density of the solution is 1.41 g/ml

1000 g of the solution will have a volume =

Mass/Density = 1000/1.41 = 709 ml

The mass percent of nitric acid is 69%

1000 g of the solution will have =

1000× 69/100

= 690g of nitric acid

The molarity of solution is

Mass of nitric acid / Molar mass of nitric acid × Vol of Sol.

= 690/63×709

= 0.0155M

Hope it helps...