Question

calculate the concentration of nitric acid in moles per litre in a sample which has density 1.41 g mol ^-1 and the mass percentage of nitric acid in it being 69% calculate molarity molality mole fraction and normality​

Answer 1

Answer:

The density of the solution is 1.41 g/mL.

1000 g of the solution will have a volume = Mass ÷ Density

= 1000 ÷ 1.41

=709 ml.

The mass per cent of nitric acid is 69%.

1000 g of the solution will have 1000× 69 ÷ 100

=690 g of nitric acid.

The molarity of solution = Mass of nitric acid ÷ (Molar mass of nitric acid ×Volume of solution)

= 690 ÷ 63×709

=0.0155 M.