calculate the concentration of OH- ion in an aqueous solution having PH value 8
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Answer:
The answer is 10^(-6)
Explanation:
It's given that pH=8.
We know that pH + pOH = 14.
therefore,
8 + pOH = 14
so, pOH of that aqueous solution is 6.
Now,
pOH = -log([OH-]) = 6
So, [OH-] = 10^(-6)
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