Question

calculate the concentration of oxalic acid of pH 2.3 ( pka1=1.25 and pka2. =4.14 )​

Answer 1

Answer:

t=∞

t=0

H

2

C

2

O

4

+

0

1mmol

2NaOH

→

1mmol

3mmol

Na

2

C

2

O

4

+

1mmol

−

2H

2

O

[OH

−

]=

50 mL

1 mmol

=0.02 M

[H

+

]=5×10

−13

⇒pH=X=12.3

On adding

t=∞

t=0

H

2

SO

4

,

0

1mmol

OH

−

+

1mmol

2mmol

H

+

→H

2

O

H

+

+C

2

O

4

2−

→HC

2

O

4

−

pH=Y=

2

pK

1

+pK

2

=2.7

Explanation:

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