Question

calculate the coordinates of point S which divides the line segment joining A(-2,-5) and B(6,-1) in ratio 5:3


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Answer 1

Answer:

S(3, -2.5)

Step-by-step explanation:

using Section formula,

$x = (mx2 + nx1) \div m + n$

{5(6)+3(-2) } ÷5+3

=(30-6)÷8

=24÷8

=3

$y =( my2 + ny1 )\div m + n$

{5(-1)+3(-5)}÷5+3

=(-5-15)÷8

=(-20)÷8

=-2.5

therefore the coordinates of point S are (3,-2.5)