Question

Calculate the cost required to paint a container which is in shape of a right circular cylinder having a base radius of 7 m and height 13 m. If the painting cost of the container is INR 2.5/m2. (Take π = 22/7)

Answer 1

Answer:

Radius = 7m

Height =13m

Total Surface Area of the cylinder = 2πr(h+r)

= 2×22/7× 7 × (13+7)

=2×22/7×7×20sq.m

Cost of painting =₹2.5/sq.m

Cost of painting the container =

= 2×22/7×7×20×2.5

= 44×50

=₹2200

【It is advisory to complete the calculations in question like this one in the end . I hope this solution would help you . 】

Answer 2

Answer:

The cost of painting the container would be INR 1505

Step-by-step explanation:

From the above question,

They have given :

To calculate the cost required to paint a container which is in shape of a right circular cylinder having a base radius of 7 m and height 13 m. If the painting cost of the container is INR 2.5/m2.

The surface area of the right circular cylinder can be calculated as follows:

A = 2 * π * r * h + 2 * π * $r^{2}$

Where,

r = radius of the base

h = height of the cylinder

Substituting the given values, we get:

A = 2 * π * 7 * 13 + 2 * π * $7^{2}$

A = 602 $m^{2}$.

So, the cost of painting the container would be:

Cost = A * INR 2.5 /  $m^{2}$.

Cost = 602 * 2.5

Cost = INR 1505

Hence, the cost of painting the container would be INR 1505

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