Question

Calculate the coulomb force between two Alpha particles separated by a distance 3.2 into 10 raise to power minus 2 metres

Answer 1

★$\color{darkblue}\underline{\underline{\sf Given-}}$

$\bullet$ Two ${\sf \alpha - particles}$ have charges ${\sf Q_1=2×1.6×10^{-19}C\:and \: Q_2=2×1.6×10^{-19}C}$

$\bullet$ Separated by distance (d) = ${\sf 3.2×10^{-2}m}$

★$\color{darkblue}\underline{\underline{\sf To \: Find-}}$

$\bullet$ Coulomb's force between two ${\sf \alpha - particles}$.

★$\color{darkblue}\underline{\underline{\sf Formula \: Used-}}$

✏ Coulomb's Law

$\color{violet}\bullet\underline{\boxed{\sf F=9×10^9×\dfrac{Q_1Q_2}{d^2}}}$

★$\color{darkblue}\underline{\underline{\sf Solution-}}$

$\implies{\sf F=9×10^9×\dfrac{2×1.6×10^{-19}×2×1.6×10^{-19}}{2^2}}$

$\implies{\sf F=\dfrac{9×10^9× 2.56×10^{-38}}{4}}$

$\implies{\sf F=\dfrac{23.04×10^{-29}}{4}}$

$\color{red}\implies{\sf F=5.76×10^{-29}\:N}$

★$\color{darkblue}\underline{\underline{\sf Answer-}}$

Coulomb's force between two ${\sf \alpha - particles}$ is $\color{red}{\sf 5.76×10^{-29}\:N}$