calculate the coulomb's force between 2 alpha particles separated by distance 3.2×10‐¹⁵
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Answer:
90N
Explanation:
Charge on each alpha particle=2e=3.2 * 10^(-19) C
F=1/(4πε) q1q2/r^2
=9*10^9 x [3.2*10^(-19)]^2 / [3.281-^(-15)]^2
=9*10^9 x [10^(-4)]^2
=9 x 10^9 x 10^(-8)
=9 x 10^(9-8)
=9*10
=90N
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