Question

calculate the Coulomb's force between alpha particle
and electron placed at a distance
9.68 10-15m in vacuum?
​

Answer 1

$\huge\underline{\underline{\bf \orange{Question-}}}$

Falculate the Coulomb's force between alpha particle and electron placed at a distance ${\sf 9.68×10^{-15}}$m in vacuum?

$\huge\underline{\underline{\bf \orange{Solution-}}}$

$\sf{Given}\begin{cases}{\sf Charge\:on\:\alpha \: particle=+2}\\{\sf Charge\:on\:e^-=1.6×10^{-19}C}\\{\sf Distance\: Between\:2\: charge=9.68×10^{-15}m}\end{cases}$

$\sf{To\:Find}\begin{cases}{\sf Coulomb's\:Force}\end{cases}$

➩ Coulomb's Law

❏$\large{\boxed{\bf \blue{F=\dfrac{1}{4π\epsilon_o}×\dfrac{q_1q_2}{r^2}} }}$

$\implies{\sf \pink{\dfrac{1}{4π\epsilon_o}=9×10^9}}$

$\implies{\sf F=9×10^9×\dfrac{2×1.6×10^{-19}}{(9.68×10^{-15})} }$

$\implies{\sf F =\dfrac{28.8×10^{-10}}{93.7×10^{-30}} }$

$\implies{\sf F=0.3×10^{20} }$

$\implies{\bf \red{F=3×10^{19}N} }$

$\huge\underline{\underline{\bf \orange{Answer-}}}$

Coulomb's force is ${\bf \red{3×10^{19}N}}$.

Answer 2

$\mathtt{ \huge{ \fbox{Solution :)}}}$

Given ,

• The magnitude of alpha particle is 2 × (1.6 × 10^(-19)) C
• The magnitude of electron is 1.6 × 10^(-19) C
• The distance between alpha particle and electron is 9.68 × (10)^-15

We know that , the electrostatic force between two charges is given by coulombs law i.e

$\large \mathtt{ \fbox{Electrostatic \: force =k \frac{ q_{1}q_{2} }{ {(r)}^{2} } }}$

Where , K = coulombs constant which is equal to 9 × (10)^9 Nm²/C²

Therefore ,

$\sf \mapsto F= \frac{9 \times {(10)}^{9} \times 2 \times (1.6) \times {(10)}^{ - 19} \times1.6 \times {(10)}^{ - 19} }{9.68 \times {(10)}^{ - 15} } \\ \\ \sf \mapsto F = \frac{9 \times 2 \times 16 \times 16 \times {(10)}^{(9 - 19 - 19 + 2)} }{968 \times {(10)}^{( - 15 + 2)} } \\ \\ \sf \mapsto F = \frac{18 \times 256 \times {(10)}^{ (- 27)}}{968 \times {(10)}^{ (- 13)} } \\ \\\sf \mapsto F = \frac{4608 \times {(10)}^{ (- 27 + 13)} }{968} \\ \\\sf \mapsto F = 4.760 \times {(10)}^{ - 14} \: \: newton$

Hence , the electrostatic force is 4.760 × (10)^(-14) newton

______________ Keep Smiling ☺