Question

Calculate the coulomb's force between electron and nucleus in normal hydrogen atom?

Answer 1

Answer:

The magnitude of charge on electron and proton is same and equal to 1.6 × 10 − 19 C i.e. q1 = q2 = 1.6 × 10^−19 C. The distance between the two charges is r=0.05 nm = 0.05×10^−9m . Hence, the electrostatic force of attraction between a proton and an electron in a hydrogen atom is 9.216 × 10^−8 N .

Explanation:

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