Question

calculate the critical velocity of the satellite to be located at 2000 kilometre above the surface of the earth ​

Answer 1

Answer:

Well, this problem is connected with the concept of circular motion and the forces which act on a body in such a motion. In order to find the velocity we ought to approximate that the motion is perfectly circular. Since we have circular motion, the gravitational force is equalized by the centrifugal one. From this follows :

GMm/( R+h)^2 = mv^2 /R+h, we cancel some terms on both sides and we finally get :

v=sqrt((GM/(R+h))

where G is the gravitational constant- 6.67408 × 10^(-11) N .m^2/kg^2

M is the mass of Earth, R is its radius and h is the height above its surface.

Numerically we get v (orbital velocity) to be around 7758 m/s.

Hope it helps :)