Question

calculate the critical velocity (vc) of the satellite to be located at 35780 km above the surface of the earth.​

Answer 1

Answer:

Explanation:

this velocity is called orbital velocity/...

V = [g(0) * R / 1 + h/R]^1/2         derive it from Fg =Fc

 = 3.084 KM/sec

Answer 2

The critical velocity of the satellite to be located at 35780 km above the surface of the earth is 3.08 km/s.

Explanation:

The critical velocity of the satellite is given by :

$v=\sqrt{\dfrac{GM}{R+h}}$

G is universal gravitational constant

R is radius of Earth, $R=6.4\times 10^6\ m$

h is the height above the surface of Earth, $h=35780\times 10^3\ m$

M is mass of Earth

$v=\sqrt{\dfrac{6.67\times10^{-11}\times6\times10^{24}}{6.4\times10^{6}+35780\times10^{3}}}$

$v=3080.24\ m/s$

or

v = 3.08 km/s

So, the critical velocity of the satellite to be located at 35780 km above the surface of the earth is 3.08 km/s.

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Calculate the critical velocity of the satellite to be located at 35780 km above the surface of the earth.​ ?

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