Question

Calculate the current and resistance of a 100 W, 200V electric bulb.

Answer 1

Power = V^2/R

Given, P = 100 W
V = 200

R = V^2/P
R = (200)^2/100
R = 400 ohm

Now Current ,I = V/R
I = 200/400
I = 1/2 = 0.5 A

Hope This Helps You!

Answer 2

Answer:

Current and resistance of electric bulb are $400\Omega$ and $0.5A$ repectively.

Explanation:

General formula of electrical Power, $P=\frac{V^2}{R}$ ----(1)

where, is the voltage across the bulb,

and R is the resistance of the bulb.

Given: $P=100W; V=200V$

Putting in equation (1), we get,

$100=\frac{(200)^2}{R}$

$\implies R=\frac{200^2}{100} = 400\Omega$

Form ohm's law: $V=IR$

$\implies I=\frac{V}{R}$

$\implies I=\frac{200}{400}=0.5A$

Current and resistance of electric bulb are $400\Omega$ and $0.5A$ repectively.

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