Calculate the current drawn by the primary of a transformer 90% efficient which steps down 220 v to 22 v if the output resistance is 440
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The current drawn by the primary will be 5.55 miliampere
Explanation :
on the secondary side , voltage, V₂ = 22 v
Resistance, R = 440
we know that current = voltage/resistance
so I₂ = 22/440 = 0.05 A
Output power = Voltage x current
= 22 x 0.05
= 1.1 watt
since the efficiency of the transformer = output power/input power
=> 1.1/P₁ = 0.9
=> P₁ = 1.1/0.9 = 1.22
we know that
input power = input voltage x input current
=> P₁ = V₁ x I₁
=> I₁ = P₁/V₁ = 1.22/220 = 0.0055 A = 5.5 mA
Hence the current drawn by the primary will be 5.55 miliampere
muthurajanandhi2001:
thanku so much brainly bravo
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