Question

calculate the current flowing in each of the branch using kvl?​

Answer 1

Answer:

Explanation:

Mesh 1:-2I

1

​

+2(I

1

​

+I

2

​

)=6v

⟹4I

1

​

−2I

2

​

=6v

⟹2I

1

​

−I

2

​

=3→(1)

Mesh 2:-4I

2

​

+2(I

1

​

+I

2

​

)=2v

⟹6I

2

​

−2I

1

​

=2→(2)

Equating (2) and (1)

I

2

​

=1A

I

1

​

=2A