calculate the current flowing through a wire of resistance 10 ohm connected to a cell with potetial difference of 2
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Answered by
7
V=2v
R=10 ohm
I=?
V=IR
So, I=V/R
I=2/10
Do
I=1/5 Amperes
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Answered by
3
Answer:0.2amp
Explanation:
According to ohm's law,
V=IR
=>I=V/R
=>I=2/10
=>I=0.2amp
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