Question

calculate the current flowing through the circuit shown below

Answer 1

Hi.
Hope this helps u!!

Answer 2

Answer:

Current flowing, I = 0.1 A

Explanation:

In the given figure, the resistors R₁ and R₂ are in series. So, the equivalent resistance will be:

$R'=30+30=60\ \Omega$

Now R' and R₃ are in parallel with each other. Now their equivalent will be given by :

$\dfrac{1}{R_{eq}}=\dfrac{1}{R'}+\dfrac{1}{R_3}$

$R_{eq}=20\ \Omega$

We know that the ohm's law gives the relationship between the electric current and voltage. Mathematically, it can be written as :

V = I R

$I=\dfrac{V}{R}$

Given that, V = 2 Volts

So, $I=\dfrac{2}{20}$

I = 0.1 A

Hence, the current flowing through the given circuit is 0.1 A.