Question

Calculate the current flows through the 10 Ω resistor in the circuit comprising of 20 Ω, 10 Ω and 5 Ω connected in parallel when 6 V potential difference is applied through the battery?    ​

Answer 1

Answer:

R = 20/ 9 ohm

I = 2.7 A

Explanation:

in parallel,

1/R = 1/10 + 1/20 + 1/10 + 1/5

= 9 / 20

R = 20 / 9 ohm

V = IR

6= I × 20/9

I = 54/ 20

= 27/ 10

= 2.7 A

Answer 2

Answer:

R=20/9 ohm

l=2.7 A

Explanation:

in parallel ,

1/R=1/10+1/20+1/10+1/15

=9/20

R=20/9 ohm

v=IR

6=I×20/9

I=54/20

=27/10

=2.7 A