Question

- Calculate the current rating for the fuse of an appliance with power consumption of 10 KW
and voltage of 230 V.
​

Answer 1

P = VI ; I = P/V ; 10000/230 = 43.47 A

Answer 2

Given: Power, P = 10KW = $10\times 10^{3}W$

Potential Difference,V = 230V

Find: We have to calculate the current

Solution: We have the expression of the power in terms of potential difference and the current.

We have the given value of the electric power and the potential difference.

$Power = Electric Potential \times Electric Current \\\\\\P = V\times I\\\\\\I = \dfrac{P}{V}$

Now we put the value of electric potential and the electric current,

$I = \dfrac{10\times10^{3} }{230}\\\\I = 43.4782A$

So, the current rating for the fuse of an appliance is 43.4782A