Calculate the current strength and number of moles of electrons required to produce 2.369*10^-3 kg of Cu from CuSO4 solution in one hour
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If l coulomb of charge will be passed in 1 second .
Charge in one hour = 1 x 60 x 60 = 3600 x I C
Reaction of Cu will be ,
Cu²⁺ + 2e⁻ = Cu
Two moles of electron will be required to form one mole of Cu :
2 x 96485 C of charge = 63.59 g
3600 x I C of charge = 63.59 x 3600I / (2 x 96485) = 2.369 g
I = (2.369 x 2 x 96485) / (3600 x 63.59)
I = 2 A
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