calculate the current through each resistance in the circuit given alongside.
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Rp=4x4/4+4=2ohm Rs=2+2+2=6ohm V=6V I=6/6=1 Current=1 amp. Oops didn't read the question carefully. Sorry. I told you the total current. I guess someone already answered it.
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the total resistance of the circuit is 6 ohm
so the total current will be V=IR
then 6=i×6
;I=6amp
if we calculate the current passing through each resistance will be
V=ir
so 6 =I ×2
so i of first resistance will pass current of 3 amp , second resistance will also pass current of 3 ohm because this is parallel combination and it's value is 2 ohm and the last resistance will also pass current of 3 amp.
so the total current will be V=IR
then 6=i×6
;I=6amp
if we calculate the current passing through each resistance will be
V=ir
so 6 =I ×2
so i of first resistance will pass current of 3 amp , second resistance will also pass current of 3 ohm because this is parallel combination and it's value is 2 ohm and the last resistance will also pass current of 3 amp.
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