Physics, asked by rachit6491, 1 year ago

calculate the current through each resistance when resistnce of 2ohm is connected in series with resistamce of 2.5ohm and four resistance of 2 ohm in parallel

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Answered by rakesh8161p4o3sm
1

1/Rp = 1/2 + 1/2+ 1/2+ 1/2


= 4/2


Rp = 2/4 = 0.5 ohm


This Rp is connected in series with 2 ohm and 2.5 ohm


So Rs = 0.5 + 2.5+ 2 =5 ohm


The current is through the circuit V/R


= 1.5 / 5 = 15/50 = 3/10 = 0.3 Ampere


Since the resistors are connected in series, the current will be the same.


So the current flowing in 2 ohm and 2.5 ohm and 0.5 ohm is same


Only it will be shared in parallel resistors


So, V = IR = 0.3 x 0.5 = 0.15V


Since, V is same in parallel, the current in each resistance because all resistors in parallel have same resistance is :-


I = V/R = 0.15/2 = 0.075 Ampere



Thank you! Hope it helps.....

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