Question

Calculate the currents
I, I and l in the
given Wheatstone's
network of resistors.
The internal resistance
of the 6 V battery is
0.402.
А
G=4012
I 2
2
3.22
W
612
IN
D
+
M
0.4.12
6 VOLT
Ans. 1.5 A, 0,9 A. 0.6​

Answer 1

Answer:

due to wheatstone's network.

current through G is zero circuits will look like as shown.

total resistance is

9+6

9×6

Ω+.4Ω=3.6Ω+.4Ω=4Ω.

current i=

4Ω

6V

=1.5A

current i

1

bu using current division

i

1

=

9+6

9

×i=

15

9

×1.5=.9A

similiarly, i

2

=

6+9

6

×i=

15

6

×1.5=.6A

Explanation:

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