Question

Calculate the de-Brogile wavelength of an electron that has been accelerated from rest through a potential difference of 1keV​

Answer 1

Answer:

The e/m ratio is known as specific charge where, e is the charge on particle and m is mass of the particles.

For neutrons ⇒ charge is zero.

mass =1.6×10 ^−27 amu

For proton ⇒ charge =1.6×10 ^−19 C

mass =1.6×10 ^−27 amu

For electron ⇒ charge =1.6×10 ^−19 C

mass =9.1×10 ^−31 amu

For α−particle ⇒ charge ⇒2×1.6×10 ^−19 C

mass ⇒4×1.6×10^ −27 amu

From these data, it can be concluded that neutron has least (e/m) specific charge and electron has high e/m ratio.

n<α<p<e