Question

calculate the De Brogile wavelength of electron which has been accelerated from rest on application of potential of 400

Answer 1

Answer:

Electron is accelerated to a potential of 400V.

Thus its kinetic energy K=400eV

de-Broglie wavelength λ=

2mK

h

∴ λ=

2(9.1×10

−31

)×400×1.6×10

−19

6.6×10

−34

Or λ=

1.08×10

−23

6.6×10

−34

=6.1×10

−11

m ⟹ λ=0.06nm