Question

calculate the de-Brogle wavelength associated with electron whose speed is 0.01 part of the speed of light​

Answer 1

Answer:

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Answer 2

Answer:

by de- Broglie wavelength theory

lambda= planks constant/p where p is momentum

so therefore lambda= planks constant/mv since p=mv

lambda = 6.626*10^-34/9.1*10^-31x3*10^6

since velocity of electron is 3x10^6m/s

and momentum is 9.1x10^-31kg

hence use that lambda formula

values are given ans will be easier

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