Question

CALCULATE THE DE BROGLEIS WAVELENGTH OF THE TENNIS BALL OF MASS 600 G MOVING WITH A VELOCITY OF 10 M/S

Answer 1

Explanation:

The de Broglie wavelength is the wavelength, λ, associated with a particle and is related to its momentum, p, through the Planck constant, h.

λ = h/p = h/mv

h = 6.63 × 10–34 Js

m = 60 g = 0.06 kg = 6 x 10-2 kg

v = 10 m/s

λ = h/mv = (6.63 x 10-34)/(10 x 6 x 10-2)

λ ≅ 10-33 m

Answer 2

Answer:-

$\implies \: \boxed{\bf{\lambda \: = {10}^{</em><em>-</em><em>34} \: or \: 10 \times {10}^{</em><em>-</em><em>3</em><em>5</em><em>} }}$

Step - by - step explanation:-

To find :-

Find De Broglei's wavelength.

Given :-

Mass(m) = 600 g = 600÷ 1000 kg

Velocity (v)= 10 m/s

Solution :-

We know that,

$\bf{ \lambda \: = \frac{h}{p}}$

$here \: \\ \bf{\lambda \: = de \: broglei '\: s \: wavelength \: }\\ \\ \bf{ h \: = \: plank 's\: constant }\\ \bf{\because \: h \: = 6.6 \times {10}^{-34} } \\ \\ \bf{ p \: = \: momentum = mass \: \times velocity} \\ \\ \therefore \: \bf{\lambda \: = \frac{6.6 \times {10}^{-34} }{ \frac{600}{1000} \times 10} } \\ \\ \implies \: \bf{ \lambda \: = 1.1 \times {10}^{-34} } \\ \\ \implies \: \bf{ \lambda \: = 11 \times {10}^{-35} }$

By round off rule -

$\implies \: \bf{\lambda \: \cong \: 10 \times {10}^{</em><em>-</em><em>3</em><em>5</em><em>} \: = {10}^{</em><em>-</em><em>3</em><em>4</em><em>} }$