Calculate the de-Broglie wavelength associated with an electron with velocity
2.05 107
ms–1
.
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1
Answer:
3.548 × 10^-11 m
Explanation:
v = 2.05 × 10^7 m/s
m = 9.10939 × 10^-31 kg
h = 6.62 × 10^-34
According to de Brogile's Equation
lambda(wavelength) = h/mv
lambda = 6.62 × 10^-34
___________
9.10939 × 10^-31 × 2.05 × 10^7
wavelength = 3.548 × 10^-11 m
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