Chemistry, asked by rbinurani, 8 days ago

Calculate the de-Broglie wavelength associated with an electron with velocity

2.05  107

ms–1

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Answers

Answered by mayank7918
1

Answer:

3.548 × 10^-11 m

Explanation:

v = 2.05 × 10^7 m/s

m = 9.10939 × 10^-31 kg

h = 6.62 × 10^-34

According to de Brogile's Equation

lambda(wavelength) = h/mv

lambda = 6.62 × 10^-34

___________

9.10939 × 10^-31 × 2.05 × 10^7

wavelength = 3.548 × 10^-11 m

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