Question

Calculate the de Broglie wavelength of a 5 g bullet that
is moving at 340 m/s. Will the bullet exhibit wavelike
properties?
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Answer 1

Answer:

Explanation:

lambda =planks constant/mass*velocity

given mass=5g=5*10^-3kg

planks constant=6*10^-34

lambda(wavelength)=6*10^-34/5*10^-3*340

                                 =   0.0035*10^-31 m

HOPE IT HELPS.

Answer 2

Answer:

3.9×10^-34

Explanation:

Mass of a bullet (m) = 5 g = 5×10^-3 kg

Velocity of a moving bullet (v) = 340 m/s

Debroglie's wavelength of a bullet (lamda) = ?

We have ,

hf = mc^2

h×c/lamda = mc^2 [Therefore f =c/lamda]

lamda = h/mc

For the particle moving with velocity 'v' ,

lamda = h/mv

= 6.62×10^-34/(5×10^-3×340)

= 3.9×10^-34 m

Since the value of wavelenth is very low so the moving bullet of 5g with velocity 340 m/s doesnot exhibit wavelike properties.