Question

calculate the de Broglie wavelength of a Proton of momentum 2.55×10^-22 kg m S ^-1 .
please give me correct answer ​

Answer 1

as per formula,

lemda = h/p

= 6.6×10^-34/2.55×10^-22

= 2.59 × 10^-12m

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Answer 2

Explanation:

wavelength = h/p

wavelength = 6.626*10^-34/2.55*10^-22

wavelength = 2.59*10^-12