Calculate the de Broglie wavelength of an electron travelling with a speed equal to 1% less of the speed of light. Or Draw the electronic configuration of Cu,(Z=29), Cr(Z=24), Fe2+ (Z=26)
Answers
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1
λ=
p
h
=
mv
h
v=
100
1
×c=
100
1
×3×10
8
=3×10
6
m/s.
λ=
9.1×10
−31
×3×10
6
6.626×10
−34
=242pm
Hence, option C is correct.
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p
h
=
mv
h
v=
100
1
×c=
100
1
×3×10
8
=3×10
6
m/s.
λ=
9.1×10
−31
×3×10
6
6.626×10
−34
=242pm
Hence, option C is correct.
Hope it’s helpful to you
Plz mark me as brainlist
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