Question

Calculate the de-Broglie wavelength

of an electron that has been accelerated

from rest through a potential difference

of 1 keV.

Answer 1

use the formula for wavelength
$= \frac{h}{ \sqrt{2mev} }$
where h=6.626*10^-34
m=9.1*10^-31
e=1.6*10^-19
v=1kev