Question

Calculate the de Broglie wavelength of CO2 moving with a velocity of 440m/s.

Answer 1

Hello!

• λ = h / mv
where, λ = wavelength

• m =  Mass of CO₂ molecule
• Mass of 1 mole of CO₂ = 44 g 

Thus,
Mass of 1 molecule of CO₂ would be (in Kg)  =0.044 / 6.022 × 10²³ kg

• v = Velocity of CO₂

Then,

λ = 6.626 × 10⁻³⁴ Js × 6.022 × 10²³ / 0.044 kg × 440 ms⁻¹

λ =2.061 × 10⁻¹¹ m

λ = 20.61 × 10⁻¹² m

λ = 20.61 pm

Cheers!