Question

Calculate the debrogile wavelength of electron orbiting n=2

Answer 1

By De-Broglie’s Equation, λ=h/(mv) …(i)

plank’s constant, h = 6.626 X 10^(-34) Js

mass of electron, m = 9.1 X 10^(-31) kg

velocity of electron in first orbit of hydrogen atom, v’=2.18 X 10^6 m/s

velocity of electron in second orbit (n=2) of hydrogen atom, v=v’/n

v = 1.09 X 10^6 m/s

mv = 9.919 X 10^(-25)

putting values in eq. (i)

λ= (6.626 X 10^(-34)) /(9. 919 X 10^(-25)) m

λ = 6.680 X 10^(-10) m

λ = 6.680 Å(armstrong)

HOPE THIS HELPS YOU!!