Question

calculate the decrease in
K.E. of a moving body if its
velocity redude to half of
its initial velocity & mass
increase by double of the
Original mass

please answer....​

Answer 1

Answer:

it was the same as the one I have is a little too much for

Answer 2

Answer:

3/4 th of initial value

Explanation:

Let u = x , then v = 1/2 x

Let initial mass = m

then new mass = 2m

K.E.

= 1/2 m ( v^2 - u^2 )

= 1/2 × 2m { ( 1/2 x )^2 - ( x )^2 }

= m ( 1/4 x^2 - x^2 )

= m { (x^2 - 4 x^2 ) ÷ 4 }

= m × ( -3 x^2 / 4 )

= -3mx^2 / 4

Therefore K.E. becomes 3 / 4 of initial value .