Calculate the decrease in the kinetic energy of a moving body if it's velocity reduces to one third of the initial velocity
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If initial kinetic energy of the body is mv²/2 and its velocity decreases to one third.
Therefore the new kinetic energy, is
m(v/3)²/2 =(1/9)mv²/2
the decrease in kinetic energy = mv²/2-(1/9)mv²/2 = (8/9)mv²/2
percentage decrease =
{ {(8/9)mv²/2}/mv²/2}×100
8×100/9 =88.89%
Therefore the new kinetic energy, is
m(v/3)²/2 =(1/9)mv²/2
the decrease in kinetic energy = mv²/2-(1/9)mv²/2 = (8/9)mv²/2
percentage decrease =
{ {(8/9)mv²/2}/mv²/2}×100
8×100/9 =88.89%
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