calculate the decrease in the kinetic energy of a moving body if its velocity is reduced to half of the initial velocity ?? Please solve it.
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initial kinetic energy(K1)=1/2mv square
now,
velocity is v/2
so the final kinetic energy(K2)=1/2m (v/2) square
now decrease in kinetic energy=K1-K2
=1/2mv square-1/2m (v/2 square)
on solving this we get
=3mv square/8
I hope it will help you
now,
velocity is v/2
so the final kinetic energy(K2)=1/2m (v/2) square
now decrease in kinetic energy=K1-K2
=1/2mv square-1/2m (v/2 square)
on solving this we get
=3mv square/8
I hope it will help you
aarti1123:
understand it well
please help me
okkk
we know that 1/2mv square is the initial value
yes
our ans is 3/8mv square...we can written it-----3/4 [1/2mv square]------and this can be written as 3/4 [initial value]---it is our answer
understood dear????
yes
guddd
I hope you are satisfied with my answer
Answered by
0
hi ....feels nice to help
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