Calculate the degeneracy of the level of the hydrogen atom having energy – RH / 25.
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Explanation:
Energy in H-atom
E=
n
2
R
H
But, given that E=
9
R
H
⇒n
2
=9
n=3
As here n=3 thus there are 3 orbits.
In general, for any energy level n, the degeneracy is given by n2
So when n= 3, the degeneracy is 9.
When n=3, the possible combinations of (n,l.m) are (3, 2, -2), (3,2, -1), (3, 2, 0), (3, 2, 1), (3, 2, 2), (3, 1, -1), (3, 1, 0), (3, 1, 1), and (3, 0, 0)
Hence D is the correct answer.
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