Question

Calculate the degree of dissociation is molar conductivity and limiting molar conductivity is 32.76Scm2mol-1 and 390.5Scm2 mol-1.

Answer 1

Answer:

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Answer 2

Answer:

dear mate here's your answer :-

Given,K = 7.896 × 10 - 5 S m - 1

c = 0.00241 mol L - 1

Then, molar conductivity, Am = K/c

= 32.76S cm2 mol - 1

Again, Amº = 390.5 S cm2 mol - 1

Now,

= 0.084

Dissociation constant,

= (0.00241 mol L-1)(0.084)2 / (1-0.084)

= 1.86 × 10 - 5 mol L - 1

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