Question

Calculate the degree of dissociation of 0.0024 M acetic acid if conductivity of this solution is 8.0 X 10^-5 S cm^-1
Given molar conductivity of Hydrogen is = 349.65 cm^2 mol^-1
and molar conductivity of Ch3Coo is 40.9 S cm^2 mol^-1​

Answer 1

Answer:

Calculate the degree of dissociation of 0.0024 M acetic acid if conductivity of this solution is 8.0 x 10-5 S cm-1 . λ°H+ = 349.6S cm2 mol-1; λ°cH3 coo- = 40.9 S cm-1 α = 33.33 S cm2 mol-1/390.5 S cm2mol-1 = 0.085Read more on Sarthaks.com - https://www.sarthaks.com/504456/calculate-the-degree-of-dissociation-0024-acetic-acid-conductivity-this-solution-is-10-cm